# Python – Convert Octal String to Integer

In this tutorial, we will look at how to convert an octal number (as a string) to an integer in Python with the help of examples.

## How to convert octal string to integer in Python?

You can use the Python built-in `int()` function to convert an octal string to an integer in Python. Pass the oct string as an argument. The following is the syntax –

```# oct string to int
int(oct_str, 8)```

The `int()` function also takes an optional argument, `base` to identify the base of the value passed. For example, use `16` as the base to convert hex string, use `8` as the base for an octal string, etc.

Although, the `int()` function is capable of inferring the base from the string passed, it’s a good practice to explicitly specify the base.

## Examples

Let’s look at some examples of using the above syntax to convert an oct string to an int.

### Oct string with prefix to int

Let’s convert an octal number (as a string) with the prefix `'0o'` to an integer using the `int()` function.

```# oct string representing 1024
oct_str = '0o2000'
# oct to int
num = int(oct_str, 8)
print(num)```

Output:

`1024`

Here we have an oct string representing the number `1024` with the prefix `'0o'`. We use the `int()` function to convert the oct string to an integer. You can see that we get `1024` as the output.

### Oct string without prefix to int

Let’s now try to convert an oct string without a prefix to int using the `int()` function. You don’t need to change any arguments as the `int()` function is capable to handle the oct string irrespective of the presence of the prefix.

```# oct string representing 1024 without '0o' prefix
oct_str = '2000'
# oct to int
num = int(oct_str, 8)
print(num)```

Output:

`1024`

Here we pass the oct string without the `'0o'` prefix to the `int()` function with `base` as 8. We get the same output as above.

For more on the Python `int()` function, refer to its documentation.

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