In this tutorial, we will look at how to check if a set contains an element or not in Python with the help of some examples.

## How to check if an element is in a set?

You can use the membership operator `in`

to check if a set contains an element or not in Python. The following is the syntax:

# check if element e is in set a e in a

It returns a boolean value. `True`

if the element is present in the set and `False`

if it isn’t.

Let’s look at an example –

# create a set a = {1, 2, 3} # check if 3 is in a print(3 in a)

Output:

True

Here we check whether the element `3`

is in the set a or not. We get True as the output because the set `a`

, here, contains the element `3`

.

Let’s look at another example.

# create a set a = {1, 2, 3} # check if 4 is in a print(4 in a)

Output:

False

Here we get `False`

as the output because the set `a`

does not contain the element `4`

.

Alternatively, you can also use the set issubset() function to check whether a set contains an element or not. The idea is to check whether the set contains a subset with the element we want to check for. Here’s an example.

# create a set a = {1, 2, 3} # check if 3 is in a print({3}.issubset(a)) # check if 4 is in a print({4}.issubset(a))

Output:

True False

We get the correct result.

Note that you should prefer the membership operator `in`

to using the issubset() function for checking whether a set contains an element or not as it is simple and intuitive.

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